(x+2)^2=3x+16

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Solution for (x+2)^2=3x+16 equation: 



(x+2)^2=3x+16

We move all terms to the left:

(x+2)^2-(3x+16)=0

We get rid of parentheses

(x+2)^2-3x-16=0

We add all the numbers together, and all the variables

-3x+(x+2)^2-16=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+2)^2=16

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